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Q.
The equivalent inductance between $A$ and $B$ is
Electromagnetic Induction
Solution:
The equivalent circuit diagram is as shown in the figure. Here, all the inductances are connected in parallel. Hence, the equivalent inductance between $A$ and $B$ is
$\frac{1}{L_{A B}}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{4}{4}=1\, H$
or $L_{A B}=1 H$
