1. Tardigrade
  2. Question
  3. Chemistry
  4. The equivalent conductance of an infinitely dilute solution of NH4Cl is 150 and the ionic conductance of OH- and Cl- ions are 198 and 76 respectively. If the equivalent conductance of a 0.01 N solution of NH4OH is 9.6. What will be its degree of dissociation?

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Q. The equivalent conductance of an infinitely dilute solution of $NH_{4}Cl$ is $150$ and the ionic conductance of $OH^{-}$ and $Cl^{-}$ ions are $198$ and $76$ respectively. If the equivalent conductance of a $0.01\, N$ solution of $NH_{4}OH$ is $9.6$. What will be its degree of dissociation?

Electrochemistry

Solution:

$\wedge^{\infty}NH_{4}OH =150-76 +198 =272$
$\alpha=\frac{9.6}{272}=0.0353$