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Chemistry
The equivalent conductance of a weak acid such as HF
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Q. The equivalent conductance of a weak acid such as HF
Electrochemistry
A
can be determined by extrapolation of measurements on dilute solutions of HCl, HBr and HF
24%
B
can be determined by measurement on very dilute solution of HF
22%
C
can be determined by measurement on dilute solutions of NaF, NaCl and HCl
37%
D
in an undefined quantity
18%
Solution:
Kohlrausch’s Law
$\Lambda_{eq} \left(NaF\right) +\Lambda_{eq} \left(HCl\right)- \Lambda_{eq}\left(NaCl\right) = \Lambda_{eq} HF$