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Q. The equivalent capacitance between the points A and B in the following circuit is:

Bihar CECEBihar CECE 2005Electrostatic Potential and Capacitance

Solution:

The two capacitors each of value $ 1.5\,\mu F $ are in parallel, so their equivalent capacitance.
$ {{C}_{1}}=1.5+1.5=3\,\mu F $
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Now, three capacitors each of value $ 3\,\mu F $ are in series. Hence, their equivalent capacitance is given by
$ \frac{1}{C}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3} $
or $ \frac{1}{C}=\frac{3}{3} $
or $ C=1\,\mu F $