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Q. The equilvalent resistance and potential difference between $A$ and $B$ for the circuit respectively arePhysics Question Image

JIPMERJIPMER 2004

Solution:

The equivalent resistance between $A$ and $B$ is
$\frac{1}{R'}=\frac{1}{6}+\frac{1}{6}+\frac{1}{3}=\frac{2}{3}$
or $R'=\frac{3}{2}=1.5\, \Omega$
Now the equivalent resistance between $A$ and $B$ is
$R''=1.5+2.5=4\, \Omega$
Now by Ohm's law, potential difference. between $A$ and $B$ is given by
$V_{A}-V_{B} =i R=2 \times 4.0$
$=8$ volt