Question

The equilibrium, $NH_{4}HS\left(\right.s\left.\right)\rightleftharpoons NH_{3}\left(\right.g\left.\right)+H_{2}S\left(\right.g\left.\right)$ , is followed to set-up at $127^\circ C$ in a closed vessel. The total pressure at equilibrium was 20 atm. The $K_{C}$ for the reaction is

• A. $0.092 \, \text{}\text{M}^{2}$
• B. $0.085 \, \text{}\text{M}^{2}$
• C. $3.045 \, \text{}\text{M}^{2}$
• D. None of these

Answer 1

Answer: (A)

$pNH_{3}=pH_{2}S=\frac{20}{2}=10 \, \text{atm}$

$K_{P}=pNH_{3}\times pH_{2}S$

$=100 \, \text{at}\text{m}^{2}$

$K _{ P }= K _{ C }( RT )^{\Delta n }$

$100= K _{ C }(0.0821 \times 400)^{2}$

$K _{ C }=0.092 M ^{2}$