1. Tardigrade
  2. Question
  3. Chemistry
  4. The equilibrium constant of the reaction SO2(g) + 1/2 O2(g) leftharpoons SO3(g) is 4 × 10-3 atm-1/2. The equilibrium constant of the reaction 2SO3(g) leftharpoons 2SO2(g) + O2(g) would be:

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Q. The equilibrium constant of the reaction
$SO_{2}(g) + 1/2 O_{2}(g) \rightleftharpoons SO_{3}(g)$ is $4 \times 10^{-3} atm^{-1/2}$. The equilibrium constant of the reaction
$2SO_{3}(g) \rightleftharpoons 2SO_{2}(g) + O_{2}(g)$ would be:

Equilibrium

Solution:

$SO_{2}(g)+\frac{1}{2} O_{2}(g) \to SO_{3}(g)\,\,\,\,\,\,K_{p}=4 \times 10{-3}$
$SO_{3} \to SO_{2} (g) + \frac{1}{2} O_{2} (g) \,\,\,\,\,\, K'_{p} = \frac{1}{K_{p}}$
$ 2SO_{3} \to 2SO_{2} +O_{2} (g) \,\,\,\,\, K'_{p} =( \frac {1}{4 \times 10^{-3}})$
$K''_{p} =(K'_{p})_{2} =[\frac{1}{4 \times 10^{-3}}] ^{2} =[ \frac{1000}{4}]$
$=6250 =625 \times 10^{2} =6.25 \times 10^{4}$ atm