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Q.
The equilibrium constant for the reaction $ N{{H}_{4}}N{{O}_{2}}(s){{N}_{2}}(g)+2{{H}_{2}}O(g) $ is given by:
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Solution:
The equilibrium constant for the reaction $ N{{H}_{4}}N{{O}_{2}}(s){{N}_{2}}(g)+2{{H}_{2}}O(g) $ is given by $ {{K}_{c}}=\frac{[{{N}_{2}}]{{[{{H}_{2}}O]}^{2}}}{[N{{H}_{4}}N{{O}_{2}}]} $