1. Tardigrade
  2. Question
  3. Chemistry
  4. The equilibrium constant for the reaction, N2+3H2leftharpoons 2NH3 at 400 K is 41. The equilibrium constant for the reaction, (1/2)N2+(3/2)H2leftharpoons NH3 at the same temperature will be closest to

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The equilibrium constant for the reaction,
$N_{2}+3H_{2}{\rightleftharpoons} 2NH_{3}$
at $400 \,K$ is $41$. The equilibrium constant for the reaction, $\frac{1}{2}N_{2}+\frac{3}{2}H_{2}{\rightleftharpoons} NH_{3}$
at the same temperature will be closest to

KVPYKVPY 2009Equilibrium

Solution:

$N_{2}+3H_{2}{\rightleftharpoons} 2NH_{3}K_C=4.1 ...(i) $
$\frac{1}{2}N_{2}+\frac{3}{2}H_{2}{\rightleftharpoons} NH_{3} ....(ii)$
We divide equation $(i)$ by $2$ to get equation $(ii)$
$\therefore $ The new equilibrium constant, $K_C'$
for Eq. (ii) will be the square root of $K_C' $
Eq. (i), i.e.
$K_{C}'=\sqrt{K_{C}}$
$K_{C}'=\sqrt{41}=6.4$