1. Tardigrade
  2. Question
  3. Chemistry
  4. The equilibrium constant for the reaction A( g )+2 B( g ) arrow C( g ) is 0.25 dm 6 mole -2. In a volume of 5 dm 3, what amount of A must be mixed with 4 moles of B to yield 1 mole of C at equilibrium.

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Q. The equilibrium constant for the reaction $A_{( g )}+2 B_{( g )} \rightarrow C_{( g )}$ is $0.25 \,dm ^6 \,mole ^{-2}$. In a volume of $5\, dm ^3$, what amount of A must be mixed with 4 moles of $B$ to yield 1 mole of $C$ at equilibrium.

NEETNEET 2022Equilibrium

Solution:

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$k_{ C }=0.25=\frac{[ C ]}{[ A ][ B ]^2} \Rightarrow[ A ]=\frac{[ C ]}{\left[ B ^2\right](0.25)}$
$\frac{n-1}{5}=\frac{1}{5 \times 0.25 \times \frac{2^2}{5^2}}=25 \Rightarrow n=26$ mols