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  4. The equilibrium constant for the following reaction is <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/c-rphp9lkfwb75xhcx.jpg />

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Q. The equilibrium constant for the following reaction is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Subtracting (ii) from (i) gives the desired equation,
Hence, equilibrium constant $= \frac{1 0^{- 9}}{1 0^{- 2 0}} = 1 0^{1 1} \text{.}$