1. Tardigrade
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  3. Chemistry
  4. The equilibrium constant for mutarotation α-D leftharpoons β-D Glucose is 1.8. What percentage of α form remains at equilibrium?

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Q. The equilibrium constant for mutarotation $\alpha-D \rightleftharpoons \beta-D$ Glucose is $1.8$. What percentage of $\alpha$ form remains at equilibrium?

Delhi UMET/DPMTDelhi UMET/DPMT 2011Equilibrium

Solution:

image
$K=\frac{\alpha}{1-\alpha}=1.8$
Solving $\alpha=0.642$
$1-\alpha=0.358$
Percent of $\alpha -D$ glucose remaining at equilibrium
$=35.8 \%$