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  4. The equilibrium constant for certain reaction is 100. If the value R is given to be 2 cal K-1 mol-1 then standard Gibb's free energy change will be

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Q. The equilibrium constant for certain reaction is 100. If the value R is given to be 2 $cal \, K^{-1} \, mol^{-1}$ then standard Gibb's free energy change will be

Thermodynamics

Solution:

$\Delta$ G$^\circ$ = - 2.303 RT log K = - 2.303 $\times$ 2 $\times$ 298 $\times$ log 100 = -2.303 $\times$ 2 $\times$ 298 $\times$ 2 = -2745.2 cal = -2.745 kcal