Question

The equations of the transverse and conjugate axes of the hyperbola $16 x^2-y^2+64 x+4 y+44=0$, are respectively

• A. $x=2, y+2=0$
• B. $x=2, y=2$
• C. $y=2, x+2=0$
• D. None of these

Answer 1

Answer: (C)

The given equation can be written as
$(4 x+8)^2-(y-2)^2=-44+64-4 $
$\rightarrow \frac{16(x+2)^2}{16}-\frac{(y-2)^2}{16}=1$
Transverse and conjugate axes are $y=2, x=-2$
$\rightarrow x+2=0$