Question

The equation of travelling wave is $ y=60\,\cos $ $ (1800t-6x) $ y where y in microns, in seconds and x in metres. The ratio of maximum particle velocity to velocity of wave propagation is :

• A. $ 3.6 $
• B. $ 3.6\times {{10}^{-6}} $
• C. $ 3.6\times {{10}^{-1}} $
• D. $ 3.6\times {{10}^{-4}} $

Answer 1

Answer: (D)

Comparing the given equation to the standard equation of wave $ {{\upsilon }_{0}}=\omega A $ and $ c=\frac{\omega }{k} $ $ \frac{{{\upsilon }_{0}}}{c}=\frac{\omega A}{\omega \text{/}k}=kA=6\times 60\times {{10}^{-6}} $ $ =3.6\times {{10}^{-4}} $