Thank you for reporting, we will resolve it shortly
Q.
The equation of the right bisector plane of the segment joining $(2,3,4)$ and $(6,7,8)$ is
Three Dimensional Geometry
Solution:
If the given points be $A (2,3,4)$ and $B (6,7,8)$, then their mid-point $N(4,5,6)$ must lie on the plane. The direction ratios of $AB$ are i.e., $1, 1, 1$.
$\therefore $ The required plane passes through $N (4,5,6)$ and is normal to $AB$. Thus its equation is
$1(x-4)+1(y-5)+1(z-6)=0 $
$\Rightarrow x + y + z=15$
