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Mathematics
The equation of the diameter of the circle (x-2)2+(y+1)2=16 which bisects the chord cut off by the circle on the line x-2 y-3=0 is
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Q. The equation of the diameter of the circle $(x-2)^2+(y+1)^2=16$ which bisects the chord cut off by the circle on the line $x-2 y-3=0$ is
Conic Sections
A
$x+2 y=0$
23%
B
$2 x+y-3=0$
33%
C
$3 x+2 y-4=0$
35%
D
none
9%
Solution:
Required diameter is $\perp$ to given line.
Hence $y+1=-2(x-2)$
$\Rightarrow 2 x+y-3=0$