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  4. The equation of the circle with centre (0,2) and radius 2 is x 2+ y 2- m y =0. The value of m is

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Q. The equation of the circle with centre $(0,2)$ and radius 2 is $x ^{2}+ y ^{2}- m y =0$. The value of $m$ is

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Solution:

Here $h=0, k=2$ and $r=2$. Therefore, the required equation of the circle is:
$(x-0)^{2}+(y-2)^{2}=(2)^{2}$
or $x^{2}+y^{2}-4 y+4=4$ or $x^{2}+y^{2}-4 y=0$