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  4. The equation of the circle passing through the point (1, 0) and (0, 1) and having the smallest radius is -

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Q. The equation of the circle passing through the point (1, 0) and (0, 1) and having the smallest radius is -

AIEEEAIEEE 2011Conic Sections

Solution:

Circle whose diametric end points are (1, 0) and (0, 1) will be of smallest radius.
$(x - 1)(x - 0) + (y - 0) (y - 1) = 0$
$x^2 + y^2 - x - y = 0$