Thank you for reporting, we will resolve it shortly
Q.
The equation of the bisector of the acute angle between the lines $2 x-y+4=0$ and $x-2 y=1$ is
Straight Lines
Solution:
Clearly, from the figure, the origin is contained in the acute angle. Writing the equations of the lines as
$2 x-y+4=0$ and $-x+2 y+1=0$,
the required bisector is
$\frac{2 x-y+4}{\sqrt{5}}=\frac{-x+2 y+1}{\sqrt{5}}$
