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  4. The equation of tangent to the parabola y2=4x at point (1, 2) is

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Q. The equation of tangent to the parabola $ {{y}^{2}}=4x $ at point (1, 2) is

Rajasthan PETRajasthan PET 2005

Solution:

Equation of tangent at (1, 2) is
$ 2y=2(x+1) $ $ [\because y{{y}_{1}}=2(x+{{x}_{1}})] $
$ \Rightarrow $ $ y=x+1 $ $ \Rightarrow $ $ x-y+1=0 $