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Q. The equation of simple harmonic motion of a particle is $a+4\pi ^{2}x=0$ where $a$ is the instantaneous linear acceleration at displacement $x$ . The frequency of motion is

NTA AbhyasNTA Abhyas 2020Oscillations

Solution:

Comparing $a+4\pi ^{2}x=0$ with standard equation of simple harmonic motion $a+\omega ^{2}x=0$
$\omega ^{2}=4\pi ^{2},\omega =2\pi $
$2\pi n=2\pi ,n=1Hz$