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Mathematics
The equation of incircle of the triangle formed by common tangents to the circles x2+y2=4 and x2+y2-6x+8=0 is
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Q. The equation of incircle of the triangle formed by common tangents to the circles $x^{2}+y^{2}=4$ and $x^{2}+y^{2}-6x+8=0$ is
NTA Abhyas
NTA Abhyas 2022
A
$x^{2}+y^{2}=1$
B
$x^{2}+y^{2}-6x+8=0$
C
$x^{2}+y^{2}-6x+9=0$
D
$x^{2}-y^{2}=1$
Solution:
Note that circles touch each other externally, hence the smaller circle is incircle of the triangle formed by common tangents.