Question

The equation of a wave on a string of linear mass density $0.04\,kgm^{- 1}$ is given by,
$y=0.02\left(m\right)sin \left[2 \pi \left(\frac{t}{0.04 \left( s \right)} - \frac{x}{0.50 \left( m \right)}\right)\right]$
The tension in the string is (in $10^{- 2 }N$ ):

Answer 1

From given equation $-V=\frac{\lambda }{T}=\frac{0.50}{0.04}$
Now $V=\sqrt{\frac{T}{\mu }} \, \Rightarrow T=v^{2}\mu $
$=\left(12.5\right)^{2}\times 0.04$
$=6.25=625\times 10^{- 2} \, N$