Question

The equation of a circle with centre $(5,4)$ and touch the $y$ axis is

• A. $x^{2}+y^{2}-10 x-8 y-16=0$
• B. $x^{2}+y^{2}-10 x-8 y-61=0$
• C. $x^{2}+y^{2}+10 x+8 y+16=0$
• D. $x^{2}+y^{2}-10 x-8 y+16=0$

Answer 1

Answer: (D)

Centre $(5,4)$ circle touches $Y$-axis So, radius $=5$ units
Equation of circle $\Rightarrow (x-5)^{2}+(y-4)^{2}=5^{2}$
$\Rightarrow x^{2}+y^{2}-10 x-8 y+16=0$