1. Tardigrade
  2. Question
  3. Chemistry
  4. The equation k =(6.5 × 1012 s -1) e -26000 K / T is followed for the decomposition of compound A. The activation energy for the reaction is kJ mol -1. [nearest integer] (Given: R =8.314 J K -1 mol -1 )

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Q. The equation
$k =\left(6.5 \times 10^{12} s ^{-1}\right) e ^{-26000 \,K / T }$
is followed for the decomposition of compound $A$. The activation energy for the reaction is ___$kJ\,mol ^{-1}$. [nearest integer]
(Given: $R =8.314 \,J \,K ^{-1}\, mol ^{-1}$ )

JEE MainJEE Main 2022Chemical Kinetics

Solution:

$K = Ae e ^{- Ea / RT }=\left(6.5 \times 10^{12} s ^{-1}\right) e ^{-26000 K / T }$
$\frac{ Ea }{8.314}=26000$
$Ea =216.164 \,kJ / mol .$