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  4. The equation 3MnO42- + 4H+ → 2MnO4- + MnO2 + 2H2O represents

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Q. The equation
$3MnO_4^{2-} + 4H+ \to 2MnO_4^- + MnO_2 + 2H_2O$
represents

The d-and f-Block Elements

Solution:

image
shows disproportionation since the oxidation state of $Mn$ changes from $+6$ to $+7 (MnO_4)$ and $+4 (MnO_2)$.