1. Tardigrade
  2. Question
  3. Chemistry
  4. The entropy values (in .JK -1 mol -1) of H 2(g)=130.6, Cl 2(g)=223.0 and HCl (g)=186.7 at 298 K and 1 atm pressure. Then entropy change for the reaction: H 2(g)+ Cl 2(g) longrightarrow 2 HCl (g) is :

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Q. The entropy values (in $\left.JK ^{-1} mol ^{-1}\right)$ of $H _{2}(g)=130.6,\,\,Cl _{2}(g)=223.0$ and $HCl (g)=186.7$ at $298\, K$ and 1 atm pressure. Then entropy change for the reaction : $H _{2}(g)+ Cl _{2}(g) \longrightarrow 2 HCl (g)$ is :

JIPMERJIPMER 2006Thermodynamics

Solution:

$\Delta S^{\circ} =2 S^{\circ}{ }_{ HCl }-\left(S_{ H _{2}}^{\circ}+S_{ Cl _{2}}^{\circ}\right) $
$=2 \times 186.7-(130.6+223.0)$
$=19.8\, JK ^{-1} mol ^{-1}$