1. Tardigrade
  2. Question
  3. Chemistry
  4. The enthalpy of vaporization of liquid water using the data: (i). H2(g)+((1/2))O2(g) arrow H2O(.l.) Δ H=-285.77 k J / m o l (ii). H2(g)+((1/2))O2(g) arrow H2O(.g.) , Δ H=-241.84 k J / m o l in kJ/mol is

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Q. The enthalpy of vaporization of liquid water using the data:

(i). $H_{2}(g)+\left(\frac{1}{2}\right)O_{2}\left(g\right) \rightarrow H_{2}O\left(\right.l\left.\right)$

$\Delta H=-285.77 \, k J / m o l$

(ii). $H_{2}\left(g\right)+\left(\frac{1}{2}\right)O_{2}\left(g\right) \rightarrow H_{2}O\left(\right.g\left.\right)$ ,

$\Delta H=-241.84 \, k J / m o l$ in kJ/mol is

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

Enthalpy of vapourisation of $\text{H}_{\text{2}} \text{O}$ is

$\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})$
i.e. (ii)-(i)
Enthalpy of vaporization of liquid water $=285.77-241.84=+43.93 \, kJ \, mol^{- 1}$