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  4. The enthalpy of formation of ammonia is -46 2kJ mol-1. The enthalpy change for the reaction 2NH3 -----> N2 + 3H2 is

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Q. The enthalpy of formation of ammonia is $-46 2kJ mol^{-1}$. The enthalpy change for the reaction $2NH_3 -----> N_2 + 3H_2$ is

Thermodynamics

Solution:

$2NH_3 \rightarrow N_2 + 3H_2$
2 moles
The enthalpy of formation of ammonia
= - 46 kJ $mol^{-1}$
$\Delta$H of given reaction = -2 $\times$ (- 46) = 92 kJ