1. Tardigrade
  2. Question
  3. Chemistry
  4. The enthalpy change involved in the oxidation of glucose is -2880kJmol- 1 . Twenty five percent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk one kilometer, what is the maximum distance that a person will be able to walk after eating 120 g of glucose?

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Q. The enthalpy change involved in the oxidation of glucose is $-2880kJmol^{- 1}$ . Twenty five percent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk one kilometer, what is the maximum distance that a person will be able to walk after eating 120 g of glucose?

NTA AbhyasNTA Abhyas 2022

Solution:

Total energy involved in the oxidation of glucose $=-2880$ $kJmol^{- 1}$ .
As twenty five percent of this energy is available for muscular work.
So energy available for muscular work $=\frac{2880 \times 25}{100}=720$ $kJmol^{- 1}$
Energy available for muscular work from 120 g glucose $=\frac{720 \times W_{g l u c o s e}}{m o l e c u l a r w e i g h t}=\frac{720 \times 120}{180}=480kJ$
As 100 kJ energy is enough for = 1 km
so 480 kJ energy is enough for $=\frac{480 \times 1}{100}=4.8km$