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Q. The enthalpy change for the transition of liquid water to steam is $40.8\, kJ\, mol ^{-1}$ at $373\,K$. Calculate the entropy of vaporisation of water.

ManipalManipal 2018

Solution:

$\Delta S _{\text {vap }}=\frac{\Delta H _{\text {vap }}}{ T }$
$\because \Delta H _{\text {vap }}=40.8\, kJ\, mol ^{-1}, T =373 \,K$
$\Delta S _{\text {vap }}=\frac{40.8 \times 10^{3}}{373}=109.4 \,JK ^{-1}\, mol ^{-1}$