1. Tardigrade
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  3. Chemistry
  4. The enthalpy change for a given reaction at 298 K is x J mol. If the reaction occurs spontaneously at 298 K, the entropy change at that temperature

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Q. The enthalpy change for a given reaction at 298 K is x J mol. If the reaction occurs spontaneously at 298 K, the entropy change at that temperature

Thermodynamics

Solution:

It is because of the fact that for spontaneity the value of $\Delta G = (\Delta H - T\Delta S)$ should be < 0.
. If $\Delta$S is -ve the value of T$\Delta$S has to be numerically less than $\Delta$H.
or Value of $\Delta$S has to be numerically less than $\Delta$H/T i.e., x/ 298