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  4. The enthalpy change (Δ H) for the neutralization of M HCl by caustic potash in dilute solution at 298 K is:

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Q. The enthalpy change $ (\Delta H) $ for the neutralization of M $ HCl $ by caustic potash in dilute solution at 298 K is:

MGIMS WardhaMGIMS Wardha 2006

Solution:

$ \underset{\begin{smallmatrix} (strong \\ acid \end{smallmatrix}}{\mathop{HCl}}\,+\underset{\begin{smallmatrix} (strong \\ base) \end{smallmatrix}}{\mathop{KOH}}\,KCl+{{H}_{2}}O $ In this reaction, $ HCl $ is the .strong acid and $ KOH $ is the base and it has been found that the heat of neutralization of a strong acid with a strong base is always constant i. e., 57.3 kJ.