1. Tardigrade
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  3. Chemistry
  4. The enthalpies of combustion of carbon and carbon monoxide are -390 kJ and -278 kJ respectively. The enthalpy of formation of CO in kJ is

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Q. The enthalpies of combustion of carbon and carbon monoxide are $-390 kJ$ and $-278 kJ$ respectively. The enthalpy of formation of $CO$ in $kJ$ is

Thermodynamics

Solution:

$C+O_{2}\to CO_{2}; \Delta H = -290 kJ ....\left(1\right)$
$CO +\frac{1}{2}O_{2}\to CO_{2}; \Delta H = -278 kJ ...\left(2\right)$
By eq. (1) and eq. (2), we get
$C+ \frac{1}{2}O_{2}\to CO; \Delta H = - 112 kJ$