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Physics
The energy stored in an inductor of self inductance L henry carrying a current of I ampere is
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Q. The energy stored in an inductor of self inductance $L$ henry carrying a current of $I$ ampere is
Electromagnetic Induction
A
$\frac{1}{2}L^{2}\,I$
12%
B
$\frac{1}{2}LI^{2}$
68%
C
$LI^{2}$
13%
D
$L^{2}I$
7%
Solution:
The energy stored in an inductor is
$U=\frac{1}{2}LI^{2}$