Question

The energy per mole per degree of freedom of an ideal gas is

• A. $ \frac {3}{2} k_{B}T $
• B. $ \frac {1}{2}k_{B}T$
• C. $\frac {3}{2} RT $
• D. $\frac {1}{2} RT $

Answer 1

Answer: (D)

The energy per mole per degree of freedom of an ideal gas is
$E=\left(\frac{1}{2} K_{B} T\right)\left(N_{A}\right)$
Where, $T$ = absolute temperature
$N_{A}=$ Avogadro's number
$K_{B}=$ Boltzmann's constant
$\because R=N_{A} K_{B}$
Therefore, $E=\frac{1}{2} R T$