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Physics
The energy of the incident photon is 20 eV and the work function of the photosensitive metal is 10 eV, the stopping potential is
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Q. The energy of the incident photon is 20 eV and the work function of the photosensitive metal is 10 eV, the stopping potential is
Dual Nature of Radiation and Matter
A
5 V
17%
B
10 V
59%
C
15 V
19%
D
30 V
5%
Solution:
$V_0 = \frac{(20 - 10) eV}{e} = \frac{10 \times e}{e} $ 10 V