Question

The energy of second Bohr orbit of the hydrogen atom is $ -328\, kJ\, mol^{−1} $ ; hence the energy of fourth Bohr orbit would be

• A. $ -41\, kJ\, mol^{−1} $
• B. $ -1312\, kJ\, mol^{−1} $
• C. $ -164\, kJ\, mol^{−1} $
• D. $ -82\, kJ\, mol^{−1} $

Answer 1

Answer: (D)

The energy of second Bohr orbit of hydrogen atom $(E_2)$ is $-328\,kJ \,mol^{−1}$ because
$E_{2}=-\frac{1312}{2^{2}}kJ\,mol^{-1}$
$\therefore E_{n}=-\frac{1312}{n^{2}}kJ\,mol^{-1}$
If $n=4$
$\therefore E_{4}=-\frac{1312}{4^{2}}\,kJ\,mol^{-1}$
$=-82\,kJ\,mol^{-1}$