Question

The energy of second Bohr orbit of the hydrogen atom is $- \text{328 kJ mol}^{- 1}$ The energy of fourth Bohr orbit would be:

• A. $- \text{41 kJ mol}^{- 1}$
• B. $- \text{82 kJ mol}^{- \text{1}}$
• C. $- \text{164 kJ mol}^{- \text{1}}$
• D. $- \text{1312 kJ mol}^{- \text{1}}$

Answer 1

Answer: (B)

We know that $E _{ n }= E _{1} \times\left(\frac{ Z }{ n }\right)^{2}$
Given $E _{2}=\frac{ E _{1}}{2^{2}}=-328 kJ mol ^{-1}$
$ E _{4}=\frac{ E _{2}}{2^{2}}=\frac{-328}{4} kJ mol ^{-1}=-82 kJ mol ^{-1} $