1. Tardigrade
  2. Question
  3. Physics
  4. The energy of photon of light is 3 eV. Then, the wavelength of photon must be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The energy of photon of light is 3 eV. Then, the wavelength of photon must be

Dual Nature of Radiation and Matter

Solution:

$E=h 8=32 V .$
$8=\frac{c}{\lambda}$
$c=3 \times 10^{8} m / s .$
$h=6.6 \times 10^{-34} Js .$
$1\,e V =1.6 \times 10^{-19}$
$ \frac{h c}{\lambda} =3 e v $
$\lambda =\frac{h c}{3 e v} $
$=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{3 \times 1.6 \times 10^{-19}}$
$=\frac{19.8 \times 10^{-26}}{4.8 \times 10^{-19}}$
$=4.125 \times 10^{-7}$
$=412.5 \times 10^{-9}$
$\lambda=412.5 \,nm$