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Q. The energy of one mole of photons of radiation of frequency $2 \times 10^{12} Hz$ in $J mol ^{-1}$ is ________. (Nearest integer)
$\left[\right.$ Given : $h =6.626 \times 10^{-34} Js$
$\left. N _{ A }=6.022 \times 10^{23} mol ^{-1}\right]$

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Solution:

For one photon $E=h v$
For one mole photon,
$E =6 \cdot 023 \times 10^{23} \times 6 \cdot 626 \times 10^{-34} \times 2 \times 10^{12}$
$ =798 \cdot 16 J $
$ \approx 798\, J$