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Q.
The energy of incident photons corresponding to maximum wavelength of visible light is
J & K CETJ & K CET 2004
Solution:
From Planck's hypothesis, the energy of a photon, of frequency vis $E=h v=\frac{h c}{\lambda}$
where $c$ is speed of light and $a$. the wavelength.
In the visible part, red colour has maximum wavelength $\lambda = 8000\,\mathring{A}$
$\therefore E=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{8000 \times 10^{-10}}$
Also, $1 eV =1.6 \times 10^{-19} J$
$\therefore E=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{8000 \times 10^{-10} \times 1.6 \times 10^{-19}}=1.547\, eV$