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  4. The energy of gamma (γ) ray photon is Eγ and that of an X-ray photon is Ex. If the visible light photon has an energy of Ev , then we can say that

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Q. The energy of gamma $(γ)$ ray photon is $E_γ$ and that of an X-ray photon is $E_x$. If the visible light photon has an energy of $E_v$ , then we can say that

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Solution:

$E_{\gamma} \geq 100 keV$
$ E_{X} =100\, eV$ to $100 \,keV $
$ E_{v} =2.48\, eV $
So, we can say that
$E_{\gamma}>E_{X}>E_{v}$