1. Tardigrade
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  3. Chemistry
  4. The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

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Q. The energy of an electron in the first Bohr orbit of H-atom is -$13.6\, eV$. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

IIT JEEIIT JEE 1998Structure of Atom

Solution:

The energy of an electron in a Bohr atom is expressed as
$E_{n}=-\frac{k Z^{2}}{n^{2}} $ where,
$k =$ Constant,
$Z =$ Atomic number,
$n =$ Orbit number
$=-13.6 \,eV$ for $H (n=1) $
when $n=2, E_{2} =\frac{-13.6}{2^{2}} \,eV =-3.40\, eV$
( $n$ can have only integral value $1,2,3, \ldots \ldots \infty$ )