1. Tardigrade
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  3. Physics
  4. The energy of an electron in nth orbit of the hydrogen atom is given by En = -(13.6/n2) eV. The energy required to raise an electron from the first orbit to the second orbit will be

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Q. The energy of an electron in $n^{th}$ orbit of the hydrogen atom is given by $E_n = -\frac{13.6}{n^2} eV$. The energy required to raise an electron from the first orbit to the second orbit will be

UP CPMTUP CPMT 2011

Solution:

$E_{1} = - \frac{13.6}{1^{2}} = -13.6 \,eV $
$ E_{2} = - \frac{13.6}{2^{2}} = -3.4 \,eV $
$ E = E_{2} - E_{1} = -3.4\,eV-\left(-13.6\right)\,eV $
$ =10.2 \,eV$