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Chemistry
The energy of an electron in first Bohr orbit of H - atom is - 13.6 eV. The energy value of electron in the excited state of Li2+ is :
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Q. The energy of an electron in first Bohr orbit of $H$ - atom is $- 13.6\, eV$. The energy value of electron in the excited state of $Li^{2+}$ is :
JEE Main
JEE Main 2014
Structure of Atom
A
-27.2 eV
0%
B
30.6 eV
25%
C
-30.6 eV
75%
D
27.2 eV
0%
Solution:
Energy of $e^{-} $ in the excited state of $ Li^{+2}$
$E=-13.6 \frac{Z^{2}}{n^{2}}$
$=-13.6\times\frac{\left(3\right)^{2}}{\left(2\right)^{2}} e V$
$=-\frac{9}{4} \times13.6 \,eV$
$=-30.6\, e N$