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  4. The energy of an electron in first Bohr orbit of H - atoms is -13.6 eV. The possible energy value of electron in the excited state of Li2+ is

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Q. The energy of an electron in first Bohr orbit of $H -$ atoms is $-13.6\, eV$. The possible energy value of electron in the excited state of $Li^{2+}$ is

WBJEEWBJEE 2011Structure of Atom

Solution:

$E_{n}=\frac{E_{1}}{n^{2}} \times Z^{2}$
For $Li ^{2+}$, the excited state, $n=2$ and $Z=3$
$\therefore E_{n} =\frac{-13.6}{2^{2}} \times(3)^{2} $
$=\frac{-13.6}{4} \times 9=-30.6 \,eV $