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Q. The energy of a photon of wavelength $ 390 \,nm $ is nearly

AMUAMU 2012Dual Nature of Radiation and Matter

Solution:

Energy of photon, $E = \frac{hc}{\lambda}$
$E = \frac{6.6 \times 10^{-34} \times 3 \times 10^8}{390 \times 10^{-9}}$
$= 5.0 \times 10^{-19}\,J$
$E = \frac{5.0 \times 10^{-19}}{1.6 \times 10^{-19}} $
$= 3.2 \,eV$