Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The energy of a photon of wavelength 390 nm is nearly

Dual Nature of Radiation and Matter

Solution:

Here, $\lambda=390\, nm$
Energy of a photon, $E=\frac{h c}{\lambda}$
Take $h c=1240 \,eV \,nm$
$\therefore E=\frac{1240\, eV\, nm }{390\, nm }=3.2 \,eV$